Value
column and a
Group
column,
determine which values belong to a given
Membership
as defined by a set of
Group
values.
This function requires the bigdata library section to be loaded.
bd.relational.divide(data, value, group, membership)
bdFrame
or
data.frame
.
NULL
, this specifies the first column
that is not the
group
column.
NULL
, this specifies all of the data set columns.
group
levels that define membership.
If
NULL
, this specifies all of
group
's
levels.
bdFrame
or
data.frame
containing
the
value
elements that satisfy the
membership
.
This function takes two inputs (
bdFrame
or
data.frame
). The output contains the
value
elements that satisfy the
membership
.
## Get the weekdays with Light and Moderate traffic traffic <- c("Light", "Moderate", "Heavy") week.congestion <- data.frame(weekdays=c(1,2,3,1), traffic=as.factor(traffic[c(1,2,2,2)])) bd.relational.divide(week.congestion, 1, "traffic", c("Light", "Moderate"))