Compute K-fn of a Point Pattern
DESCRIPTION:
Actually computes L = sqrt(K/pi).
USAGE:
Kfn(pp, fs, k=100)
REQUIRED ARGUMENTS:
- pp
-
a list such as a pp object, including components
x
and
y
- fs
-
full scale of the plot
- k
-
number of regularly spaced distances in (0,
fs
)
VALUE:
A list with components
- x
-
vector of distances
- y
-
vector of L-fn values
- k
-
number of distances returned --- may be less than
k
if
fs
is too large
- dmin
-
minimum distance between pair of points
- lm
-
maximum deviation from L(t) = t
DETAILS:
relies on the domain D having been set by
ppinit
or
ppregion
.
SEE ALSO:
,
,
,
EXAMPLES:
towns <- ppinit("towns.dat")
par(pty="s")
plot(Kfn(towns, 10), type="s", xlab="distance", ylab="L(t)")