Compute K-fn of a Point Pattern

DESCRIPTION:

Actually computes L = sqrt(K/pi).

USAGE:

Kfn(pp, fs, k=100)

REQUIRED ARGUMENTS:

pp
a list such as a pp object, including components x and y
fs
full scale of the plot
k
number of regularly spaced distances in (0, fs)

VALUE:

A list with components
x
vector of distances
y
vector of L-fn values
k
number of distances returned --- may be less than k if fs is too large
dmin
minimum distance between pair of points
lm
maximum deviation from L(t) = t

DETAILS:

relies on the domain D having been set by ppinit or ppregion.

SEE ALSO:

, , ,

EXAMPLES:

towns <- ppinit("towns.dat")
par(pty="s")
plot(Kfn(towns, 10), type="s", xlab="distance", ylab="L(t)")